Base | Representation |
---|---|
bin | 10001100111110110011… |
… | …010110000101000000011 |
3 | 11021202212001211010210202 |
4 | 101213312122300220003 |
5 | 124320132111121402 |
6 | 2324200201515415 |
7 | 153331130220623 |
oct | 21476632605003 |
9 | 4252761733722 |
10 | 1211020020227 |
11 | 427655259426 |
12 | 1768541a2b6b |
13 | 8a277701a34 |
14 | 42883d2a883 |
15 | 2177c3d1b02 |
hex | 119f66b0a03 |
1211020020227 has 2 divisors, whose sum is σ = 1211020020228. Its totient is φ = 1211020020226.
The previous prime is 1211020020187. The next prime is 1211020020263. The reversal of 1211020020227 is 7220200201121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1211020020227 - 222 = 1211015825923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1211020020199 and 1211020020208.
It is not a weakly prime, because it can be changed into another prime (1211020028227) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605510010113 + 605510010114.
It is an arithmetic number, because the mean of its divisors is an integer number (605510010114).
Almost surely, 21211020020227 is an apocalyptic number.
1211020020227 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211020020227 is an equidigital number, since it uses as much as digits as its factorization.
1211020020227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 20.
Adding to 1211020020227 its reverse (7220200201121), we get a palindrome (8431220221348).
The spelling of 1211020020227 in words is "one trillion, two hundred eleven billion, twenty million, twenty thousand, two hundred twenty-seven".
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