Base | Representation |
---|---|
bin | 10110100011101001… |
… | …10010111111101101 |
3 | 1011020222111120022011 |
4 | 23101310302333231 |
5 | 144300203304401 |
6 | 5321403521221 |
7 | 606050053510 |
oct | 132164627755 |
9 | 34228446264 |
10 | 12110213101 |
11 | 5154999388 |
12 | 241b829211 |
13 | 11acc42b8c |
14 | 82c50ad77 |
15 | 4ad291451 |
hex | 2d1d32fed |
12110213101 has 4 divisors (see below), whose sum is σ = 13840243552. Its totient is φ = 10380182652.
The previous prime is 12110213039. The next prime is 12110213113. The reversal of 12110213101 is 10131201121.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 12110213101 - 211 = 12110211053 is a prime.
It is a super-3 number, since 3×121102131013 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12110217101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 865015215 + ... + 865015228.
It is an arithmetic number, because the mean of its divisors is an integer number (3460060888).
Almost surely, 212110213101 is an apocalyptic number.
It is an amenable number.
12110213101 is a deficient number, since it is larger than the sum of its proper divisors (1730030451).
12110213101 is an equidigital number, since it uses as much as digits as its factorization.
12110213101 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1730030450.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 12110213101 its reverse (10131201121), we get a palindrome (22241414222).
The spelling of 12110213101 in words is "twelve billion, one hundred ten million, two hundred thirteen thousand, one hundred one".
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