Base | Representation |
---|---|
bin | 1011000000111010000101… |
… | …1000010101110101111011 |
3 | 1120212201121002001111120002 |
4 | 2300032201120111311323 |
5 | 3041403212400220443 |
6 | 41431205230023215 |
7 | 2356635356201462 |
oct | 260164130256573 |
9 | 46781532044502 |
10 | 12110220320123 |
11 | 3949a08726762 |
12 | 1437060347b0b |
13 | 69acb1739b13 |
14 | 2dc1d01539d9 |
15 | 1600345382b8 |
hex | b03a1615d7b |
12110220320123 has 2 divisors, whose sum is σ = 12110220320124. Its totient is φ = 12110220320122.
The previous prime is 12110220320117. The next prime is 12110220320173. The reversal of 12110220320123 is 32102302201121.
12110220320123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12110220320123 - 220 = 12110219271547 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 12110220320095 and 12110220320104.
It is not a weakly prime, because it can be changed into another prime (12110220320173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055110160061 + 6055110160062.
It is an arithmetic number, because the mean of its divisors is an integer number (6055110160062).
Almost surely, 212110220320123 is an apocalyptic number.
12110220320123 is a deficient number, since it is larger than the sum of its proper divisors (1).
12110220320123 is an equidigital number, since it uses as much as digits as its factorization.
12110220320123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 12110220320123 its reverse (32102302201121), we get a palindrome (44212522521244).
The spelling of 12110220320123 in words is "twelve trillion, one hundred ten billion, two hundred twenty million, three hundred twenty thousand, one hundred twenty-three".
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