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12110221112131 is a prime number
BaseRepresentation
bin1011000000111010000101…
…1011010111001101000011
31120212201121010112201222201
42300032201123113031003
53041403213101042011
641431205255014031
72356635366010522
oct260164133271503
946781533481881
1012110221112131
113949a0911780a
12143706066a317
1369acb195646c
142dc1d02bc4b9
15160034642cc1
hexb03a16d7343

12110221112131 has 2 divisors, whose sum is σ = 12110221112132. Its totient is φ = 12110221112130.

The previous prime is 12110221112111. The next prime is 12110221112149. The reversal of 12110221112131 is 13121112201121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12110221112131 - 233 = 12101631177539 is a prime.

It is a super-2 number, since 2×121102211121312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12110221112099 and 12110221112108.

It is not a weakly prime, because it can be changed into another prime (12110221112111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055110556065 + 6055110556066.

It is an arithmetic number, because the mean of its divisors is an integer number (6055110556066).

Almost surely, 212110221112131 is an apocalyptic number.

12110221112131 is a deficient number, since it is larger than the sum of its proper divisors (1).

12110221112131 is an equidigital number, since it uses as much as digits as its factorization.

12110221112131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 12110221112131 its reverse (13121112201121), we get a palindrome (25231333313252).

The spelling of 12110221112131 in words is "twelve trillion, one hundred ten billion, two hundred twenty-one million, one hundred twelve thousand, one hundred thirty-one".