12110433113 has 2 divisors, whose sum is σ = 12110433114. Its totient is φ = 12110433112.

The previous prime is 12110433091. The next prime is 12110433121. The reversal of 12110433113 is 31133401121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8594773264 + 3515659849 = 92708^2 + 59293^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12110433113 is a prime.

It is not a weakly prime, because it can be changed into another prime (12110433173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055216556 + 6055216557.

It is an arithmetic number, because the mean of its divisors is an integer number (6055216557).

Almost surely, 2^12110433113 is an apocalyptic number.

It is an amenable number.

12110433113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12110433113 is an equidigital number, since it uses as much as digits as its factorization.

12110433113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 12110433113 its reverse (31133401121), we get a palindrome (43243834234).

The spelling of 12110433113 in words is "twelve billion, one hundred ten million, four hundred thirty-three thousand, one hundred thirteen".