Base | Representation |
---|---|
bin | 10001100111111000011… |
… | …100001111111110111001 |
3 | 11021202221102200201121111 |
4 | 101213320130033332321 |
5 | 124320214303341431 |
6 | 2324203413240321 |
7 | 153332021566651 |
oct | 21477034177671 |
9 | 4252842621544 |
10 | 1211053965241 |
11 | 42767243385a |
12 | 1768636330a1 |
13 | 8a281758543 |
14 | 42888645361 |
15 | 217803897b1 |
hex | 119f870ffb9 |
1211053965241 has 2 divisors, whose sum is σ = 1211053965242. Its totient is φ = 1211053965240.
The previous prime is 1211053965181. The next prime is 1211053965257. The reversal of 1211053965241 is 1425693501121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1192070912400 + 18983052841 = 1091820^2 + 137779^2 .
It is a cyclic number.
It is not a de Polignac number, because 1211053965241 - 27 = 1211053965113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1211053965194 and 1211053965203.
It is not a weakly prime, because it can be changed into another prime (1211053165241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605526982620 + 605526982621.
It is an arithmetic number, because the mean of its divisors is an integer number (605526982621).
Almost surely, 21211053965241 is an apocalyptic number.
It is an amenable number.
1211053965241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211053965241 is an equidigital number, since it uses as much as digits as its factorization.
1211053965241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64800, while the sum is 40.
The spelling of 1211053965241 in words is "one trillion, two hundred eleven billion, fifty-three million, nine hundred sixty-five thousand, two hundred forty-one".
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