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1211100102022 = 2605550051011
BaseRepresentation
bin10001100111111011001…
…100001111110110000110
311021210001122111201101011
4101213323030033312012
5124320313111231042
62324212142152434
7153333122004346
oct21477314176606
94253048451334
101211100102022
11427696486028
12176876b8271a
138a28b190405
1442890814d26
152178444ea17
hex119fb30fd86

1211100102022 has 4 divisors (see below), whose sum is σ = 1816650153036. Its totient is φ = 605550051010.

The previous prime is 1211100101987. The next prime is 1211100102059. The reversal of 1211100102022 is 2202010011121.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 1211100101993 and 1211100102011.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 302775025504 + ... + 302775025507.

It is an arithmetic number, because the mean of its divisors is an integer number (454162538259).

Almost surely, 21211100102022 is an apocalyptic number.

1211100102022 is a deficient number, since it is larger than the sum of its proper divisors (605550051014).

1211100102022 is an equidigital number, since it uses as much as digits as its factorization.

1211100102022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 605550051013.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 1211100102022 its reverse (2202010011121), we get a palindrome (3413110113143).

Subtracting 1211100102022 from its reverse (2202010011121), we obtain a palindrome (990909909099).

The spelling of 1211100102022 in words is "one trillion, two hundred eleven billion, one hundred million, one hundred two thousand, twenty-two".

Divisors: 1 2 605550051011 1211100102022