Base | Representation |
---|---|
bin | 11011100010011000011111… |
… | …110110100100110111101111 |
3 | 120212211000010200101222110002 |
4 | 123202120133312210313233 |
5 | 111333231311141304403 |
6 | 1105325102013134515 |
7 | 34336624152260660 |
oct | 3342303766446757 |
9 | 525730120358402 |
10 | 121110022213103 |
11 | 35653521231250 |
12 | 116bbb2548a43b |
13 | 527681a69bc51 |
14 | 21c9a835dd367 |
15 | e00539e01188 |
hex | 6e261fda4def |
121110022213103 has 64 divisors (see below), whose sum is σ = 151816459576320. Its totient is φ = 93859207833600.
The previous prime is 121110022213093. The next prime is 121110022213127. The reversal of 121110022213103 is 301312220011121.
It is not a de Polignac number, because 121110022213103 - 246 = 50741278035439 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121110022213183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 31929874775 + ... + 31929878567.
It is an arithmetic number, because the mean of its divisors is an integer number (2372132180880).
Almost surely, 2121110022213103 is an apocalyptic number.
121110022213103 is a deficient number, since it is larger than the sum of its proper divisors (30706437363217).
121110022213103 is a wasteful number, since it uses less digits than its factorization.
121110022213103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6768.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 121110022213103 its reverse (301312220011121), we get a palindrome (422422242224224).
The spelling of 121110022213103 in words is "one hundred twenty-one trillion, one hundred ten billion, twenty-two million, two hundred thirteen thousand, one hundred three".
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