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121111110011081 is a prime number
BaseRepresentation
bin11011100010011001100000…
…101100001100100011001001
3120212211002221111021211202002
4123202121200230030203021
5111333241023130323311
61105325401552320345
734336663131353441
oct3342314054144311
9525732844254662
10121111110011081
1135653a2a271a43
12117001898430b5
135276961b699a8
1421c9b47c83121
15e005a067693b
hex6e2660b0c8c9

121111110011081 has 2 divisors, whose sum is σ = 121111110011082. Its totient is φ = 121111110011080.

The previous prime is 121111110011051. The next prime is 121111110011167. The reversal of 121111110011081 is 180110011111121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 85165581390400 + 35945528620681 = 9228520^2 + 5995459^2 .

It is a cyclic number.

It is not a de Polignac number, because 121111110011081 - 222 = 121111105816777 is a prime.

It is a super-3 number, since 3×1211111100110813 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (121111110011011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60555555005540 + 60555555005541.

It is an arithmetic number, because the mean of its divisors is an integer number (60555555005541).

Almost surely, 2121111110011081 is an apocalyptic number.

It is an amenable number.

121111110011081 is a deficient number, since it is larger than the sum of its proper divisors (1).

121111110011081 is an equidigital number, since it uses as much as digits as its factorization.

121111110011081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 20.

The spelling of 121111110011081 in words is "one hundred twenty-one trillion, one hundred eleven billion, one hundred ten million, eleven thousand, eighty-one".