Base | Representation |
---|---|
bin | 1011000000111101011111… |
… | …0011000110101010000001 |
3 | 1120212210221200222222000022 |
4 | 2300033113303012222001 |
5 | 3041412100111233343 |
6 | 41431440002303225 |
7 | 2360000113352366 |
oct | 260172763065201 |
9 | 46783850888008 |
10 | 12111133305473 |
11 | 394a337018104 |
12 | 1437276057b15 |
13 | 69b0c892bb37 |
14 | 2dc2794d046d |
15 | 16008977c568 |
hex | b03d7cc6a81 |
12111133305473 has 2 divisors, whose sum is σ = 12111133305474. Its totient is φ = 12111133305472.
The previous prime is 12111133305457. The next prime is 12111133305511. The reversal of 12111133305473 is 37450333111121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7797341386384 + 4313791919089 = 2792372^2 + 2076967^2 .
It is a cyclic number.
It is not a de Polignac number, because 12111133305473 - 24 = 12111133305457 is a prime.
It is not a weakly prime, because it can be changed into another prime (12111133305673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055566652736 + 6055566652737.
It is an arithmetic number, because the mean of its divisors is an integer number (6055566652737).
Almost surely, 212111133305473 is an apocalyptic number.
It is an amenable number.
12111133305473 is a deficient number, since it is larger than the sum of its proper divisors (1).
12111133305473 is an equidigital number, since it uses as much as digits as its factorization.
12111133305473 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 22680, while the sum is 35.
Adding to 12111133305473 its reverse (37450333111121), we get a palindrome (49561466416594).
The spelling of 12111133305473 in words is "twelve trillion, one hundred eleven billion, one hundred thirty-three million, three hundred five thousand, four hundred seventy-three".
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