1211114134141 has 4 divisors (see below), whose sum is σ = 1263771270432. Its totient is φ = 1158456997852.

The previous prime is 1211114134117. The next prime is 1211114134177. The reversal of 1211114134141 is 1414314111121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1211114134141 - 2¹¹ = 1211114132093 is a prime.

It is a super-2 number, since 2×1211114134141² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1211114137141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26328568111 + ... + 26328568156.

It is an arithmetic number, because the mean of its divisors is an integer number (315942817608).

Almost surely, 2^{1211114134141} is an apocalyptic number.

It is an amenable number.

1211114134141 is a deficient number, since it is larger than the sum of its proper divisors (52657136291).

1211114134141 is an equidigital number, since it uses as much as digits as its factorization.

1211114134141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 52657136290.

The product of its digits is 384, while the sum is 25.

Adding to 1211114134141 its reverse (1414314111121), we get a palindrome (2625428245262).

The spelling of 1211114134141 in words is "one trillion, two hundred eleven billion, one hundred fourteen million, one hundred thirty-four thousand, one hundred forty-one".