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12111211010153 is a prime number
BaseRepresentation
bin1011000000111101110001…
…1011100001100001101001
31120212211011010012202210102
42300033130123201201221
53041412230004311103
641431451415555145
72360002046005553
oct260173433414151
946784133182712
1012111211010153
11394a376970852
12143729808bab5
1369b10ba67538
142dc28595a4d3
151600914cae88
hexb03dc6e1869

12111211010153 has 2 divisors, whose sum is σ = 12111211010154. Its totient is φ = 12111211010152.

The previous prime is 12111211010083. The next prime is 12111211010167. The reversal of 12111211010153 is 35101011211121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11628181840144 + 483029170009 = 3410012^2 + 695003^2 .

It is a cyclic number.

It is not a de Polignac number, because 12111211010153 - 28 = 12111211009897 is a prime.

It is not a weakly prime, because it can be changed into another prime (12111211010183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055605505076 + 6055605505077.

It is an arithmetic number, because the mean of its divisors is an integer number (6055605505077).

Almost surely, 212111211010153 is an apocalyptic number.

It is an amenable number.

12111211010153 is a deficient number, since it is larger than the sum of its proper divisors (1).

12111211010153 is an equidigital number, since it uses as much as digits as its factorization.

12111211010153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 20.

Adding to 12111211010153 its reverse (35101011211121), we get a palindrome (47212222221274).

The spelling of 12111211010153 in words is "twelve trillion, one hundred eleven billion, two hundred eleven million, ten thousand, one hundred fifty-three".