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121112121100153 is a prime number
BaseRepresentation
bin11011100010011010011100…
…111101001100011101111001
3120212211012112221211111012111
4123202122130331030131321
5111333300111000201103
61105330050151412321
734340030156441131
oct3342323475143571
9525735487744174
10121112121100153
11356543a8a7a147
12117004103840a1
135276a9348a351
1421c9c02279ac1
15e0060e2e886d
hex6e269cf4c779

121112121100153 has 2 divisors, whose sum is σ = 121112121100154. Its totient is φ = 121112121100152.

The previous prime is 121112121100073. The next prime is 121112121100177. The reversal of 121112121100153 is 351001121211121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76746570502144 + 44365550598009 = 8760512^2 + 6660747^2 .

It is a cyclic number.

It is not a de Polignac number, because 121112121100153 - 229 = 121111584229241 is a prime.

It is not a weakly prime, because it can be changed into another prime (121112121103153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60556060550076 + 60556060550077.

It is an arithmetic number, because the mean of its divisors is an integer number (60556060550077).

Almost surely, 2121112121100153 is an apocalyptic number.

It is an amenable number.

121112121100153 is a deficient number, since it is larger than the sum of its proper divisors (1).

121112121100153 is an equidigital number, since it uses as much as digits as its factorization.

121112121100153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 22.

Adding to 121112121100153 its reverse (351001121211121), we get a palindrome (472113242311274).

The spelling of 121112121100153 in words is "one hundred twenty-one trillion, one hundred twelve billion, one hundred twenty-one million, one hundred thousand, one hundred fifty-three".