Base | Representation |
---|---|
bin | 111000011001011011… |
… | …0100111000000101011 |
3 | 102120121112002022021101 |
4 | 1300302312213000223 |
5 | 3441014214320101 |
6 | 131345504022231 |
7 | 11515163141554 |
oct | 1606266470053 |
9 | 376545068241 |
10 | 121112260651 |
11 | 473aa793aa8 |
12 | 1b580301977 |
13 | b56176b875 |
14 | 5c0cd5732b |
15 | 323c95e401 |
hex | 1c32da702b |
121112260651 has 2 divisors, whose sum is σ = 121112260652. Its totient is φ = 121112260650.
The previous prime is 121112260637. The next prime is 121112260663. The reversal of 121112260651 is 156062211121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121112260651 is a prime.
It is not a weakly prime, because it can be changed into another prime (121112261651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60556130325 + 60556130326.
It is an arithmetic number, because the mean of its divisors is an integer number (60556130326).
Almost surely, 2121112260651 is an apocalyptic number.
121112260651 is a deficient number, since it is larger than the sum of its proper divisors (1).
121112260651 is an equidigital number, since it uses as much as digits as its factorization.
121112260651 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 28.
Adding to 121112260651 its reverse (156062211121), we get a palindrome (277174471772).
The spelling of 121112260651 in words is "one hundred twenty-one billion, one hundred twelve million, two hundred sixty thousand, six hundred fifty-one".
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