Base | Representation |
---|---|
bin | 10110100011110001… |
… | …11100111001011001 |
3 | 1011021001112220022101 |
4 | 23101320330321121 |
5 | 144300443132413 |
6 | 5321443123401 |
7 | 606062241022 |
oct | 132170747131 |
9 | 34231486271 |
10 | 12111302233 |
11 | 5155572698 |
12 | 2420073561 |
13 | 11b0234834 |
14 | 82c711c49 |
15 | 4ad408edd |
hex | 2d1e3ce59 |
12111302233 has 2 divisors, whose sum is σ = 12111302234. Its totient is φ = 12111302232.
The previous prime is 12111302209. The next prime is 12111302251. The reversal of 12111302233 is 33220311121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9307811529 + 2803490704 = 96477^2 + 52948^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12111302233 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12111302233.
It is not a weakly prime, because it can be changed into another prime (12111302293) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055651116 + 6055651117.
It is an arithmetic number, because the mean of its divisors is an integer number (6055651117).
Almost surely, 212111302233 is an apocalyptic number.
It is an amenable number.
12111302233 is a deficient number, since it is larger than the sum of its proper divisors (1).
12111302233 is an equidigital number, since it uses as much as digits as its factorization.
12111302233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 12111302233 its reverse (33220311121), we get a palindrome (45331613354).
The spelling of 12111302233 in words is "twelve billion, one hundred eleven million, three hundred two thousand, two hundred thirty-three".
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