Base | Representation |
---|---|
bin | 1011000000111110000111… |
… | …0111111000011011110100 |
3 | 1120212211101111001022012200 |
4 | 2300033201313320123310 |
5 | 3041412421344030400 |
6 | 41431504441144500 |
7 | 2360004235136511 |
oct | 260174167703364 |
9 | 46784344038180 |
10 | 12111302330100 |
11 | 394a413473886 |
12 | 143730278b130 |
13 | 69b12495c1cc |
14 | 2dc293b2c308 |
15 | 160099518b00 |
hex | b03e1df86f4 |
12111302330100 has 216 divisors, whose sum is σ = 38051413720320. Its totient is φ = 3222098403840.
The previous prime is 12111302330077. The next prime is 12111302330123. The reversal of 12111302330100 is 103320311121.
12111302330100 is a `hidden beast` number, since 1 + 21 + 1 + 1 + 302 + 330 + 10 + 0 = 666.
It is an interprime number because it is at equal distance from previous prime (12111302330077) and next prime (12111302330123).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 929273184 + ... + 929286216.
Almost surely, 212111302330100 is an apocalyptic number.
12111302330100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12111302330100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19025706860160).
12111302330100 is an abundant number, since it is smaller than the sum of its proper divisors (25940111390220).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12111302330100 is a wasteful number, since it uses less digits than its factorization.
12111302330100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15399 (or 15389 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 12111302330100 its reverse (103320311121), we get a palindrome (12214622641221).
The spelling of 12111302330100 in words is "twelve trillion, one hundred eleven billion, three hundred two million, three hundred thirty thousand, one hundred".
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