Base | Representation |
---|---|
bin | 10110100011110010… |
… | …00001010001000101 |
3 | 1011021001120210212100 |
4 | 23101321001101011 |
5 | 144300444221013 |
6 | 5321443342313 |
7 | 606062344143 |
oct | 132171012105 |
9 | 34231523770 |
10 | 12111320133 |
11 | 5155585090 |
12 | 2420081999 |
13 | 11b023ca23 |
14 | 82c718593 |
15 | 4ad40e473 |
hex | 2d1e41445 |
12111320133 has 24 divisors (see below), whose sum is σ = 19092468096. Its totient is φ = 7337131200.
The previous prime is 12111320131. The next prime is 12111320159. The reversal of 12111320133 is 33102311121.
12111320133 is a `hidden beast` number, since 1 + 211 + 1 + 320 + 133 = 666.
It is not a de Polignac number, because 12111320133 - 21 = 12111320131 is a prime.
It is a super-2 number, since 2×121113201332 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12111320131) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 225316 + ... + 273842.
It is an arithmetic number, because the mean of its divisors is an integer number (795519504).
Almost surely, 212111320133 is an apocalyptic number.
It is an amenable number.
12111320133 is a deficient number, since it is larger than the sum of its proper divisors (6981147963).
12111320133 is a wasteful number, since it uses less digits than its factorization.
12111320133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51065 (or 51062 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 12111320133 its reverse (33102311121), we get a palindrome (45213631254).
It can be divided in two parts, 121113 and 20133, that added together give a triangular number (141246 = T531).
The spelling of 12111320133 in words is "twelve billion, one hundred eleven million, three hundred twenty thousand, one hundred thirty-three".
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