Search a number
-
+
1211143303142 = 2605571651571
BaseRepresentation
bin10001100111111101110…
…001000010111111100110
311021210011122210120011122
4101213331301002333212
5124320410141200032
62324220324133542
7153334155134213
oct21477561027746
94253148716148
101211143303142
11427708902733
121768895372b2
138a297107cc6
144289645cb0a
1521788135012
hex119fdc42fe6

1211143303142 has 4 divisors (see below), whose sum is σ = 1816714954716. Its totient is φ = 605571651570.

The previous prime is 1211143303129. The next prime is 1211143303213. The reversal of 1211143303142 is 2413033411121.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 302785825784 + ... + 302785825787.

It is an arithmetic number, because the mean of its divisors is an integer number (454178738679).

Almost surely, 21211143303142 is an apocalyptic number.

1211143303142 is a deficient number, since it is larger than the sum of its proper divisors (605571651574).

1211143303142 is an equidigital number, since it uses as much as digits as its factorization.

1211143303142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 605571651573.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 1211143303142 its reverse (2413033411121), we get a palindrome (3624176714263).

The spelling of 1211143303142 in words is "one trillion, two hundred eleven billion, one hundred forty-three million, three hundred three thousand, one hundred forty-two".

Divisors: 1 2 605571651571 1211143303142