1211159993 has 2 divisors, whose sum is σ = 1211159994. Its totient is φ = 1211159992.

The previous prime is 1211159947. The next prime is 1211160001. The reversal of 1211159993 is 3999511121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1207423504 + 3736489 = 34748^2 + 1933^2 .

It is an emirp because it is prime and its reverse (3999511121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1211159993 - 2²² = 1206965689 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1211159993.

It is not a weakly prime, because it can be changed into another prime (1211159903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605579996 + 605579997.

It is an arithmetic number, because the mean of its divisors is an integer number (605579997).

Almost surely, 2^1211159993 is an apocalyptic number.

It is an amenable number.

1211159993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211159993 is an equidigital number, since it uses as much as digits as its factorization.

1211159993 is an evil number, because the sum of its binary digits is even.

The product of its digits is 21870, while the sum is 41.

The square root of 1211159993 is about 34801.7239946529. The cubic root of 1211159993 is about 1065.9426489825.

The spelling of 1211159993 in words is "one billion, two hundred eleven million, one hundred fifty-nine thousand, nine hundred ninety-three".