Base | Representation |
---|---|
bin | 111000011001100011… |
… | …0011111111110010011 |
3 | 102120121210220221020102 |
4 | 1300303012133332103 |
5 | 3441021301114011 |
6 | 131350133203015 |
7 | 11515243431041 |
oct | 1606306377623 |
9 | 376553827212 |
10 | 121116426131 |
11 | 47402079648 |
12 | 1b58179046b |
13 | b56259984c |
14 | 5c0d71d391 |
15 | 323ced373b |
hex | 1c3319ff93 |
121116426131 has 2 divisors, whose sum is σ = 121116426132. Its totient is φ = 121116426130.
The previous prime is 121116426107. The next prime is 121116426161. The reversal of 121116426131 is 131624611121.
It is a weak prime.
It is an emirp because it is prime and its reverse (131624611121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121116426131 - 234 = 103936556947 is a prime.
It is a super-2 number, since 2×1211164261312 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 121116426094 and 121116426103.
It is not a weakly prime, because it can be changed into another prime (121116426161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60558213065 + 60558213066.
It is an arithmetic number, because the mean of its divisors is an integer number (60558213066).
Almost surely, 2121116426131 is an apocalyptic number.
121116426131 is a deficient number, since it is larger than the sum of its proper divisors (1).
121116426131 is an equidigital number, since it uses as much as digits as its factorization.
121116426131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1728, while the sum is 29.
The spelling of 121116426131 in words is "one hundred twenty-one billion, one hundred sixteen million, four hundred twenty-six thousand, one hundred thirty-one".
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