1211200431113 has 2 divisors, whose sum is σ = 1211200431114. Its totient is φ = 1211200431112.

The previous prime is 1211200431097. The next prime is 1211200431137. The reversal of 1211200431113 is 3111340021121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1065907575184 + 145292855929 = 1032428^2 + 381173^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211200431113 - 2⁴ = 1211200431097 is a prime.

It is not a weakly prime, because it can be changed into another prime (1211200430113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605600215556 + 605600215557.

It is an arithmetic number, because the mean of its divisors is an integer number (605600215557).

Almost surely, 2^{1211200431113} is an apocalyptic number.

It is an amenable number.

1211200431113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211200431113 is an equidigital number, since it uses as much as digits as its factorization.

1211200431113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1211200431113 its reverse (3111340021121), we get a palindrome (4322540452234).

The spelling of 1211200431113 in words is "one trillion, two hundred eleven billion, two hundred million, four hundred thirty-one thousand, one hundred thirteen".