Base | Representation |
---|---|
bin | 1011000001000000110001… |
… | …0010101100111100101101 |
3 | 1120212220020002012002021202 |
4 | 2300100030102230330231 |
5 | 3041420401041112023 |
6 | 41432103222535245 |
7 | 2360030666231540 |
oct | 260201422547455 |
9 | 46786202162252 |
10 | 12112014004013 |
11 | 394a749166a40 |
12 | 1437480b97525 |
13 | 69b209228031 |
14 | 2dc320464857 |
15 | 1600dbc45128 |
hex | b040c4acf2d |
12112014004013 has 32 divisors (see below), whose sum is σ = 15264500060160. Its totient is φ = 9335760168960.
The previous prime is 12112014004009. The next prime is 12112014004039. The reversal of 12112014004013 is 31040041021121.
It is a cyclic number.
It is not a de Polignac number, because 12112014004013 - 22 = 12112014004009 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12112014054013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6173933 + ... + 7895661.
It is an arithmetic number, because the mean of its divisors is an integer number (477015626880).
Almost surely, 212112014004013 is an apocalyptic number.
It is an amenable number.
12112014004013 is a deficient number, since it is larger than the sum of its proper divisors (3152486056147).
12112014004013 is a wasteful number, since it uses less digits than its factorization.
12112014004013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1722737.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 12112014004013 its reverse (31040041021121), we get a palindrome (43152055025134).
The spelling of 12112014004013 in words is "twelve trillion, one hundred twelve billion, fourteen million, four thousand, thirteen".
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