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121120242020147 is a prime number
BaseRepresentation
bin11011100010100010000001…
…000000000010111100110011
3120212211222111220202222011002
4123202202001000002330303
5111333413223424121042
61105333512051112215
734340435336223536
oct3342420100027463
9525758456688132
10121120242020147
1135657896027577
1211701ab7ba266b
135277788a8a056
1421ca372a1ca1d
15e0093722c132
hex6e2881002f33

121120242020147 has 2 divisors, whose sum is σ = 121120242020148. Its totient is φ = 121120242020146.

The previous prime is 121120242020119. The next prime is 121120242020159. The reversal of 121120242020147 is 741020242021121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 121120242020147 - 230 = 121119168278323 is a prime.

It is a super-2 number, since 2×1211202420201472 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (121120242020047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60560121010073 + 60560121010074.

It is an arithmetic number, because the mean of its divisors is an integer number (60560121010074).

Almost surely, 2121120242020147 is an apocalyptic number.

121120242020147 is a deficient number, since it is larger than the sum of its proper divisors (1).

121120242020147 is an equidigital number, since it uses as much as digits as its factorization.

121120242020147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3584, while the sum is 29.

Adding to 121120242020147 its reverse (741020242021121), we get a palindrome (862140484041268).

The spelling of 121120242020147 in words is "one hundred twenty-one trillion, one hundred twenty billion, two hundred forty-two million, twenty thousand, one hundred forty-seven".