Base | Representation |
---|---|
bin | 11011100010100010000001… |
… | …000000000010111100110011 |
3 | 120212211222111220202222011002 |
4 | 123202202001000002330303 |
5 | 111333413223424121042 |
6 | 1105333512051112215 |
7 | 34340435336223536 |
oct | 3342420100027463 |
9 | 525758456688132 |
10 | 121120242020147 |
11 | 35657896027577 |
12 | 11701ab7ba266b |
13 | 5277788a8a056 |
14 | 21ca372a1ca1d |
15 | e0093722c132 |
hex | 6e2881002f33 |
121120242020147 has 2 divisors, whose sum is σ = 121120242020148. Its totient is φ = 121120242020146.
The previous prime is 121120242020119. The next prime is 121120242020159. The reversal of 121120242020147 is 741020242021121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121120242020147 - 230 = 121119168278323 is a prime.
It is a super-2 number, since 2×1211202420201472 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (121120242020047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60560121010073 + 60560121010074.
It is an arithmetic number, because the mean of its divisors is an integer number (60560121010074).
Almost surely, 2121120242020147 is an apocalyptic number.
121120242020147 is a deficient number, since it is larger than the sum of its proper divisors (1).
121120242020147 is an equidigital number, since it uses as much as digits as its factorization.
121120242020147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3584, while the sum is 29.
Adding to 121120242020147 its reverse (741020242021121), we get a palindrome (862140484041268).
The spelling of 121120242020147 in words is "one hundred twenty-one trillion, one hundred twenty billion, two hundred forty-two million, twenty thousand, one hundred forty-seven".
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