Base | Representation |
---|---|
bin | 10001101000000001011… |
… | …001110110011110011111 |
3 | 11021210022220122010020100 |
4 | 101220001121312132133 |
5 | 124321021302101143 |
6 | 2324230344152143 |
7 | 153335525643222 |
oct | 21500131663637 |
9 | 4253286563210 |
10 | 1211204331423 |
11 | 42773a2a6129 |
12 | 1768a5a68653 |
13 | 8a2a6955008 |
14 | 428a05c75b9 |
15 | 2178d68c6d3 |
hex | 11a0167679f |
1211204331423 has 24 divisors (see below), whose sum is σ = 1759200318720. Its totient is φ = 803003443200.
The previous prime is 1211204331397. The next prime is 1211204331431. The reversal of 1211204331423 is 3241334021121.
1211204331423 is a `hidden beast` number, since 1 + 2 + 1 + 1 + 204 + 3 + 31 + 423 = 666.
It is not a de Polignac number, because 1211204331423 - 212 = 1211204327327 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1211204331223) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4879723 + ... + 5121923.
It is an arithmetic number, because the mean of its divisors is an integer number (73300013280).
Almost surely, 21211204331423 is an apocalyptic number.
1211204331423 is a deficient number, since it is larger than the sum of its proper divisors (547995987297).
1211204331423 is a wasteful number, since it uses less digits than its factorization.
1211204331423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 245279 (or 245276 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 1211204331423 its reverse (3241334021121), we get a palindrome (4452538352544).
The spelling of 1211204331423 in words is "one trillion, two hundred eleven billion, two hundred four million, three hundred thirty-one thousand, four hundred twenty-three".
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