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12112100019499 is a prime number
BaseRepresentation
bin1011000001000001000101…
…1010110100110100101011
31120212220110002001010100111
42300100101122310310223
53041421040101110444
641432115534315151
72360033062320544
oct260202132646453
946786402033314
1012112100019499
11394a792776717
1214374a5958ab7
1369b220cb347c
142dc32ba554cb
151600e4586234
hexb04116b4d2b

12112100019499 has 2 divisors, whose sum is σ = 12112100019500. Its totient is φ = 12112100019498.

The previous prime is 12112100019473. The next prime is 12112100019517. The reversal of 12112100019499 is 99491000121121.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12112100019499 is a prime.

It is a super-3 number, since 3×121121000194993 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (12112100119499) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056050009749 + 6056050009750.

It is an arithmetic number, because the mean of its divisors is an integer number (6056050009750).

Almost surely, 212112100019499 is an apocalyptic number.

12112100019499 is a deficient number, since it is larger than the sum of its proper divisors (1).

12112100019499 is an equidigital number, since it uses as much as digits as its factorization.

12112100019499 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11664, while the sum is 40.

The spelling of 12112100019499 in words is "twelve trillion, one hundred twelve billion, one hundred million, nineteen thousand, four hundred ninety-nine".