Base | Representation |
---|---|
bin | 1011000001000001000101… |
… | …1011001000011110110001 |
3 | 1120212220110002012012210122 |
4 | 2300100101123020132301 |
5 | 3041421040111200032 |
6 | 41432115540140025 |
7 | 2360033063104361 |
oct | 260202133103661 |
9 | 46786402165718 |
10 | 12112100100017 |
11 | 394a792821165 |
12 | 14374a5997615 |
13 | 69b221011008 |
14 | 2dc32ba769a1 |
15 | 1600e45a0012 |
hex | b04116c87b1 |
12112100100017 has 2 divisors, whose sum is σ = 12112100100018. Its totient is φ = 12112100100016.
The previous prime is 12112100099963. The next prime is 12112100100029. The reversal of 12112100100017 is 71000100121121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11977441192336 + 134658907681 = 3460844^2 + 366959^2 .
It is a cyclic number.
It is not a de Polignac number, because 12112100100017 - 210 = 12112100098993 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12112100099968 and 12112100100004.
It is not a weakly prime, because it can be changed into another prime (12112100100097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056050050008 + 6056050050009.
It is an arithmetic number, because the mean of its divisors is an integer number (6056050050009).
Almost surely, 212112100100017 is an apocalyptic number.
It is an amenable number.
12112100100017 is a deficient number, since it is larger than the sum of its proper divisors (1).
12112100100017 is an equidigital number, since it uses as much as digits as its factorization.
12112100100017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28, while the sum is 17.
Adding to 12112100100017 its reverse (71000100121121), we get a palindrome (83112200221138).
The spelling of 12112100100017 in words is "twelve trillion, one hundred twelve billion, one hundred million, one hundred thousand, seventeen".
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