Base | Representation |
---|---|
bin | 10001101000000001101… |
… | …111100011011001010001 |
3 | 11021210100022100011002102 |
4 | 101220001233203121101 |
5 | 124321024231123213 |
6 | 2324231110130145 |
7 | 153335625206240 |
oct | 21500157433121 |
9 | 4253308304072 |
10 | 1211210020433 |
11 | 427742531396 |
12 | 1768a7950955 |
13 | 8a2a7b975aa |
14 | 428a1268957 |
15 | 2178de13158 |
hex | 11a01be3651 |
1211210020433 has 32 divisors (see below), whose sum is σ = 1413581736960. Its totient is φ = 1016372111040.
The previous prime is 1211210020421. The next prime is 1211210020441. The reversal of 1211210020433 is 3340200121121.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1211210020433 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1211210020453) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 196526210 + ... + 196532372.
It is an arithmetic number, because the mean of its divisors is an integer number (44174429280).
Almost surely, 21211210020433 is an apocalyptic number.
It is an amenable number.
1211210020433 is a deficient number, since it is larger than the sum of its proper divisors (202371716527).
1211210020433 is a wasteful number, since it uses less digits than its factorization.
1211210020433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8757.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 1211210020433 its reverse (3340200121121), we get a palindrome (4551410141554).
The spelling of 1211210020433 in words is "one trillion, two hundred eleven billion, two hundred ten million, twenty thousand, four hundred thirty-three".
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