Base | Representation |
---|---|
bin | 1011000001000001000101… |
… | …1110100110111001011001 |
3 | 1120212220110010220111110222 |
4 | 2300100101132212321121 |
5 | 3041421040324323113 |
6 | 41432120011445425 |
7 | 2360033103620402 |
oct | 260202136467131 |
9 | 46786403814428 |
10 | 12112101011033 |
11 | 394a793293671 |
12 | 14374a6156875 |
13 | 69b22126c88a |
14 | 2dc32bc329a9 |
15 | 1600e46cee08 |
hex | b04117a6e59 |
12112101011033 has 2 divisors, whose sum is σ = 12112101011034. Its totient is φ = 12112101011032.
The previous prime is 12112101011011. The next prime is 12112101011041. The reversal of 12112101011033 is 33011010121121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10533451998784 + 1578649012249 = 3245528^2 + 1256443^2 .
It is a cyclic number.
It is not a de Polignac number, because 12112101011033 - 218 = 12112100748889 is a prime.
It is a super-3 number, since 3×121121010110333 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (12112101011093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056050505516 + 6056050505517.
It is an arithmetic number, because the mean of its divisors is an integer number (6056050505517).
Almost surely, 212112101011033 is an apocalyptic number.
It is an amenable number.
12112101011033 is a deficient number, since it is larger than the sum of its proper divisors (1).
12112101011033 is an equidigital number, since it uses as much as digits as its factorization.
12112101011033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 12112101011033 its reverse (33011010121121), we get a palindrome (45123111132154).
The spelling of 12112101011033 in words is "twelve trillion, one hundred twelve billion, one hundred one million, eleven thousand, thirty-three".
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