Base | Representation |
---|---|
bin | 10001101000000001110… |
… | …011101011100001111011 |
3 | 11021210100101101010011201 |
4 | 101220001303223201323 |
5 | 124321030020233311 |
6 | 2324231145235031 |
7 | 153335640333406 |
oct | 21500163534173 |
9 | 4253311333151 |
10 | 1211211102331 |
11 | 42774310021a |
12 | 1768a8192a77 |
13 | 8a2a8185b79 |
14 | 428a146ad3d |
15 | 2178e0789c1 |
hex | 11a01ceb87b |
1211211102331 has 2 divisors, whose sum is σ = 1211211102332. Its totient is φ = 1211211102330.
The previous prime is 1211211102217. The next prime is 1211211102341. The reversal of 1211211102331 is 1332011121121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1211211102331 - 219 = 1211210578043 is a prime.
It is a super-2 number, since 2×12112111023312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1211211102299 and 1211211102308.
It is not a weakly prime, because it can be changed into another prime (1211211102341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605605551165 + 605605551166.
It is an arithmetic number, because the mean of its divisors is an integer number (605605551166).
Almost surely, 21211211102331 is an apocalyptic number.
1211211102331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211211102331 is an equidigital number, since it uses as much as digits as its factorization.
1211211102331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 1211211102331 its reverse (1332011121121), we get a palindrome (2543222223452).
The spelling of 1211211102331 in words is "one trillion, two hundred eleven billion, two hundred eleven million, one hundred two thousand, three hundred thirty-one".
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