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121121221130113 is a prime number
BaseRepresentation
bin11011100010100010111011…
…010111000011011110000001
3120212212002001011010220112011
4123202202323113003132001
5111333422230102130423
61105334153144532521
734340501525430541
oct3342427327033601
9525762034126464
10121121221130113
1135658248782366
121170212ba81141
1352778b3891969
1421ca426a8d321
15e00993183b0d
hex6e28bb5c3781

121121221130113 has 2 divisors, whose sum is σ = 121121221130114. Its totient is φ = 121121221130112.

The previous prime is 121121221130069. The next prime is 121121221130137. The reversal of 121121221130113 is 311031122121121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104944801482049 + 16176419648064 = 10244257^2 + 4021992^2 .

It is a cyclic number.

It is not a de Polignac number, because 121121221130113 - 217 = 121121220999041 is a prime.

It is not a weakly prime, because it can be changed into another prime (121121221134113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60560610565056 + 60560610565057.

It is an arithmetic number, because the mean of its divisors is an integer number (60560610565057).

Almost surely, 2121121221130113 is an apocalyptic number.

It is an amenable number.

121121221130113 is a deficient number, since it is larger than the sum of its proper divisors (1).

121121221130113 is an equidigital number, since it uses as much as digits as its factorization.

121121221130113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 22.

Adding to 121121221130113 its reverse (311031122121121), we get a palindrome (432152343251234).

The spelling of 121121221130113 in words is "one hundred twenty-one trillion, one hundred twenty-one billion, two hundred twenty-one million, one hundred thirty thousand, one hundred thirteen".