Base | Representation |
---|---|
bin | 11011100010100011101111… |
… | …101111110000010001101011 |
3 | 120212212011022101221011020201 |
4 | 123202203233233300101223 |
5 | 111333431030101122311 |
6 | 1105334420302333031 |
7 | 34340532360035644 |
oct | 3342435757602153 |
9 | 525764271834221 |
10 | 121122100020331 |
11 | 356586598a6613 |
12 | 1170233628a177 |
13 | 52779c39a6a47 |
14 | 21ca4ab6b26cb |
15 | e009e53e09c1 |
hex | 6e28efbf046b |
121122100020331 has 2 divisors, whose sum is σ = 121122100020332. Its totient is φ = 121122100020330.
The previous prime is 121122100020287. The next prime is 121122100020359. The reversal of 121122100020331 is 133020001221121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121122100020331 - 27 = 121122100020203 is a prime.
It is a super-2 number, since 2×1211221000203312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 121122100020299 and 121122100020308.
It is not a weakly prime, because it can be changed into another prime (121122100020731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60561050010165 + 60561050010166.
It is an arithmetic number, because the mean of its divisors is an integer number (60561050010166).
Almost surely, 2121122100020331 is an apocalyptic number.
121122100020331 is a deficient number, since it is larger than the sum of its proper divisors (1).
121122100020331 is an equidigital number, since it uses as much as digits as its factorization.
121122100020331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 121122100020331 its reverse (133020001221121), we get a palindrome (254142101241452).
The spelling of 121122100020331 in words is "one hundred twenty-one trillion, one hundred twenty-two billion, one hundred million, twenty thousand, three hundred thirty-one".
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