Base | Representation |
---|---|
bin | 10001101000000010100… |
… | …001000100100000000011 |
3 | 11021210101012202122012112 |
4 | 101220002201010200003 |
5 | 124321041042013331 |
6 | 2324232252245535 |
7 | 153336143431565 |
oct | 21500241044003 |
9 | 4253335678175 |
10 | 1211223001091 |
11 | 427749897a04 |
12 | 1768b01708ab |
13 | 8a2aa790a5c |
14 | 428a2c87335 |
15 | 2179012932b |
hex | 11a02844803 |
1211223001091 has 2 divisors, whose sum is σ = 1211223001092. Its totient is φ = 1211223001090.
The previous prime is 1211223000997. The next prime is 1211223001159. The reversal of 1211223001091 is 1901003221121.
It is a strong prime.
It is an emirp because it is prime and its reverse (1901003221121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1211223001091 - 210 = 1211223000067 is a prime.
It is a super-2 number, since 2×12112230010912 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1211223001991) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605611500545 + 605611500546.
It is an arithmetic number, because the mean of its divisors is an integer number (605611500546).
Almost surely, 21211223001091 is an apocalyptic number.
1211223001091 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211223001091 is an equidigital number, since it uses as much as digits as its factorization.
1211223001091 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 23.
It can be divided in two parts, 121122 and 3001091, that added together give a palindrome (3122213).
The spelling of 1211223001091 in words is "one trillion, two hundred eleven billion, two hundred twenty-three million, one thousand, ninety-one".
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