Base | Representation |
---|---|
bin | 10001101000000010111… |
… | …100001100110101101100 |
3 | 11021210101201010222002110 |
4 | 101220002330030311230 |
5 | 124321044402110012 |
6 | 2324233104524020 |
7 | 153336261042444 |
oct | 21500274146554 |
9 | 4253351128073 |
10 | 1211230113132 |
11 | 427752905326 |
12 | 1768b2620610 |
13 | 8a2ac0b0c70 |
14 | 428a3bb9124 |
15 | 21790a8173c |
hex | 11a02f0cd6c |
1211230113132 has 24 divisors (see below), whose sum is σ = 3043603874416. Its totient is φ = 372686188608.
The previous prime is 1211230113131. The next prime is 1211230113139. The reversal of 1211230113132 is 2313110321121.
It is a junction number, because it is equal to n+sod(n) for n = 1211230113099 and 1211230113108.
It is not an unprimeable number, because it can be changed into a prime (1211230113131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3882147643 + ... + 3882147954.
Almost surely, 21211230113132 is an apocalyptic number.
1211230113132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1211230113132 is an abundant number, since it is smaller than the sum of its proper divisors (1832373761284).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1211230113132 is a wasteful number, since it uses less digits than its factorization.
1211230113132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7764295617 (or 7764295615 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 1211230113132 its reverse (2313110321121), we get a palindrome (3524340434253).
The spelling of 1211230113132 in words is "one trillion, two hundred eleven billion, two hundred thirty million, one hundred thirteen thousand, one hundred thirty-two".
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