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121123023130097 is a prime number
BaseRepresentation
bin11011100010100100100110…
…110001001000110111110001
3120212212020200201220222210022
4123202210212301020313301
5111333434422410130342
61105335052040013225
734340564266245032
oct3342444661106761
9525766621828708
10121123023130097
1135658a9298264a
1211702553461215
135277b10002141
1421ca558126a89
15e00a4b4849d2
hex6e2926c48df1

121123023130097 has 2 divisors, whose sum is σ = 121123023130098. Its totient is φ = 121123023130096.

The previous prime is 121123023130079. The next prime is 121123023130141. The reversal of 121123023130097 is 790031320321121.

Together with previous prime (121123023130079) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 82596124474081 + 38526898656016 = 9088241^2 + 6207004^2 .

It is a cyclic number.

It is not a de Polignac number, because 121123023130097 - 26 = 121123023130033 is a prime.

It is not a weakly prime, because it can be changed into another prime (121123023130007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60561511565048 + 60561511565049.

It is an arithmetic number, because the mean of its divisors is an integer number (60561511565049).

Almost surely, 2121123023130097 is an apocalyptic number.

It is an amenable number.

121123023130097 is a deficient number, since it is larger than the sum of its proper divisors (1).

121123023130097 is an equidigital number, since it uses as much as digits as its factorization.

121123023130097 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13608, while the sum is 35.

The spelling of 121123023130097 in words is "one hundred twenty-one trillion, one hundred twenty-three billion, twenty-three million, one hundred thirty thousand, ninety-seven".