Base | Representation |
---|---|
bin | 111000011001110000… |
… | …0000100111001110001 |
3 | 102120122021112120120122 |
4 | 1300303200010321301 |
5 | 3441030010142433 |
6 | 131350533020025 |
7 | 11515354424534 |
oct | 1606340047161 |
9 | 376567476518 |
10 | 121123130993 |
11 | 47405939057 |
12 | 1b583a84615 |
13 | b563aa6617 |
14 | 5c10586a1b |
15 | 323d8aa198 |
hex | 1c33804e71 |
121123130993 has 2 divisors, whose sum is σ = 121123130994. Its totient is φ = 121123130992.
The previous prime is 121123130899. The next prime is 121123131079. The reversal of 121123130993 is 399031321121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 76469947024 + 44653183969 = 276532^2 + 211313^2 .
It is an emirp because it is prime and its reverse (399031321121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121123130993 - 234 = 103943261809 is a prime.
It is not a weakly prime, because it can be changed into another prime (121123130593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60561565496 + 60561565497.
It is an arithmetic number, because the mean of its divisors is an integer number (60561565497).
Almost surely, 2121123130993 is an apocalyptic number.
It is an amenable number.
121123130993 is a deficient number, since it is larger than the sum of its proper divisors (1).
121123130993 is an equidigital number, since it uses as much as digits as its factorization.
121123130993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 35.
The spelling of 121123130993 in words is "one hundred twenty-one billion, one hundred twenty-three million, one hundred thirty thousand, nine hundred ninety-three".
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