Base | Representation |
---|---|
bin | 11011100010100100110010… |
… | …100000100110111001100001 |
3 | 120212212021012110121021120101 |
4 | 123202210302200212321201 |
5 | 111333440323322420413 |
6 | 1105335123354142401 |
7 | 34340602210540036 |
oct | 3342446240467141 |
9 | 525767173537511 |
10 | 121123220123233 |
11 | 356590840a1499 |
12 | 117025a9421a01 |
13 | 5277b41a75923 |
14 | 21ca57636538d |
15 | e00a5d8e7edd |
hex | 6e2932826e61 |
121123220123233 has 2 divisors, whose sum is σ = 121123220123234. Its totient is φ = 121123220123232.
The previous prime is 121123220123089. The next prime is 121123220123299. The reversal of 121123220123233 is 332321022321121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 108205931275264 + 12917288847969 = 10402208^2 + 3594063^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121123220123233 is a prime.
It is not a weakly prime, because it can be changed into another prime (121123220123333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60561610061616 + 60561610061617.
It is an arithmetic number, because the mean of its divisors is an integer number (60561610061617).
Almost surely, 2121123220123233 is an apocalyptic number.
It is an amenable number.
121123220123233 is a deficient number, since it is larger than the sum of its proper divisors (1).
121123220123233 is an equidigital number, since it uses as much as digits as its factorization.
121123220123233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 121123220123233 its reverse (332321022321121), we get a palindrome (453444242444354).
The spelling of 121123220123233 in words is "one hundred twenty-one trillion, one hundred twenty-three billion, two hundred twenty million, one hundred twenty-three thousand, two hundred thirty-three".
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