12112421130041 has 2 divisors, whose sum is σ = 12112421130042. Its totient is φ = 12112421130040.

The previous prime is 12112421130011. The next prime is 12112421130067. The reversal of 12112421130041 is 14003112421121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7700047810816 + 4412373319225 = 2774896^2 + 2100565^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12112421130041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12112421129989 and 12112421130016.

It is not a weakly prime, because it can be changed into another prime (12112421130011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056210565020 + 6056210565021.

It is an arithmetic number, because the mean of its divisors is an integer number (6056210565021).

Almost surely, 2^{12112421130041} is an apocalyptic number.

It is an amenable number.

12112421130041 is a deficient number, since it is larger than the sum of its proper divisors (1).

12112421130041 is an equidigital number, since it uses as much as digits as its factorization.

12112421130041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 12112421130041 its reverse (14003112421121), we get a palindrome (26115533551162).

The spelling of 12112421130041 in words is "twelve trillion, one hundred twelve billion, four hundred twenty-one million, one hundred thirty thousand, forty-one".