12112433 has 2 divisors, whose sum is σ = 12112434. Its totient is φ = 12112432.

The previous prime is 12112427. The next prime is 12112447. The reversal of 12112433 is 33421121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11888704 + 223729 = 3448^2 + 473^2 .

It is an emirp because it is prime and its reverse (33421121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12112433 - 2²² = 7918129 is a prime.

It is a super-2 number, since 2×12112433² = 293422066358978, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12112403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056216 + 6056217.

It is an arithmetic number, because the mean of its divisors is an integer number (6056217).

Almost surely, 2^12112433 is an apocalyptic number.

It is an amenable number.

12112433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12112433 is an equidigital number, since it uses as much as digits as its factorization.

12112433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 144, while the sum is 17.

The square root of 12112433 is about 3480.2920854434. The cubic root of 12112433 is about 229.6556472682.

Adding to 12112433 its reverse (33421121), we get a palindrome (45533554).

The spelling of 12112433 in words is "twelve million, one hundred twelve thousand, four hundred thirty-three".