12112433143 has 4 divisors (see below), whose sum is σ = 12317728680. Its totient is φ = 11907137608.

The previous prime is 12112433131. The next prime is 12112433147. The reversal of 12112433143 is 34133421121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34133421121 = 2879 ⋅11855999.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12112433143 is a prime.

It is a super-2 number, since 2×12112433143² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12112433147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102647680 + ... + 102647797.

It is an arithmetic number, because the mean of its divisors is an integer number (3079432170).

Almost surely, 2^12112433143 is an apocalyptic number.

12112433143 is a deficient number, since it is larger than the sum of its proper divisors (205295537).

12112433143 is an equidigital number, since it uses as much as digits as its factorization.

12112433143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 205295536.

The product of its digits is 1728, while the sum is 25.

Adding to 12112433143 its reverse (34133421121), we get a palindrome (46245854264).

The spelling of 12112433143 in words is "twelve billion, one hundred twelve million, four hundred thirty-three thousand, one hundred forty-three".