Base | Representation |
---|---|
bin | 1011000001000100011110… |
… | …1010001011001111101011 |
3 | 1120212222210111100120222112 |
4 | 2300101013222023033223 |
5 | 3041424421030410123 |
6 | 41432350122512535 |
7 | 2360064452201363 |
oct | 260210752131753 |
9 | 46788714316875 |
10 | 12113010013163 |
11 | 395010a4043a4 |
12 | 14376ba66574b |
13 | 69b337698867 |
14 | 2dc3b68539a3 |
15 | 1601493d8d78 |
hex | b0447a8b3eb |
12113010013163 has 2 divisors, whose sum is σ = 12113010013164. Its totient is φ = 12113010013162.
The previous prime is 12113010013033. The next prime is 12113010013229. The reversal of 12113010013163 is 36131001031121.
12113010013163 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12113010013163 - 210 = 12113010012139 is a prime.
It is not a weakly prime, because it can be changed into another prime (12113010013763) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056505006581 + 6056505006582.
It is an arithmetic number, because the mean of its divisors is an integer number (6056505006582).
Almost surely, 212113010013163 is an apocalyptic number.
12113010013163 is a deficient number, since it is larger than the sum of its proper divisors (1).
12113010013163 is an equidigital number, since it uses as much as digits as its factorization.
12113010013163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 12113010013163 its reverse (36131001031121), we get a palindrome (48244011044284).
The spelling of 12113010013163 in words is "twelve trillion, one hundred thirteen billion, ten million, thirteen thousand, one hundred sixty-three".
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