Base | Representation |
---|---|
bin | 111000011001111101… |
… | …0110010011000001001 |
3 | 102120122202201022112021 |
4 | 1300303322302120021 |
5 | 3441033303224001 |
6 | 131351343044441 |
7 | 11515501066543 |
oct | 1606372623011 |
9 | 376582638467 |
10 | 121130133001 |
11 | 47409890839 |
12 | 1b5862a0721 |
13 | b565388717 |
14 | 5c1148a693 |
15 | 323e2deba1 |
hex | 1c33eb2609 |
121130133001 has 2 divisors, whose sum is σ = 121130133002. Its totient is φ = 121130133000.
The previous prime is 121130132987. The next prime is 121130133013. The reversal of 121130133001 is 100331031121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 95944443001 + 25185690000 = 309749^2 + 158700^2 .
It is an emirp because it is prime and its reverse (100331031121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121130133001 - 25 = 121130132969 is a prime.
It is not a weakly prime, because it can be changed into another prime (121130133071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60565066500 + 60565066501.
It is an arithmetic number, because the mean of its divisors is an integer number (60565066501).
Almost surely, 2121130133001 is an apocalyptic number.
It is an amenable number.
121130133001 is a deficient number, since it is larger than the sum of its proper divisors (1).
121130133001 is an equidigital number, since it uses as much as digits as its factorization.
121130133001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 121130133001 its reverse (100331031121), we get a palindrome (221461164122).
The spelling of 121130133001 in words is "one hundred twenty-one billion, one hundred thirty million, one hundred thirty-three thousand, one".
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