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121130213310000 = 2432547011919959
BaseRepresentation
bin11011100010101011010011…
…010101011111111000110000
3120212212221020211111222100200
4123202223103111133320300
5111334044134101410000
61105342241330315200
734341240414621456
oct3342532325377060
9525787224458320
10121130213310000
1135661042612194
1211703a1b428b00
1352786b783466b
1421caa3b02a9d6
15e00d1c818500
hex6e2ad355fe30

121130213310000 has 300 divisors, whose sum is σ = 424214367136560. Its totient is φ = 32255294400000.

The previous prime is 121130213309999. The next prime is 121130213310091. The reversal of 121130213310000 is 13312031121.

121130213310000 is a `hidden beast` number, since 12 + 1 + 130 + 213 + 310 + 0 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (300).

It is a super-2 number, since 2×1211302133100002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 62130021 + ... + 64049979.

Almost surely, 2121130213310000 is an apocalyptic number.

121130213310000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 121130213310000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (212107183568280).

121130213310000 is an abundant number, since it is smaller than the sum of its proper divisors (303084153826560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121130213310000 is a wasteful number, since it uses less digits than its factorization.

121130213310000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1920694 (or 1920670 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 121130213310000 its reverse (13312031121), we get a palindrome (121143525341121).

The spelling of 121130213310000 in words is "one hundred twenty-one trillion, one hundred thirty billion, two hundred thirteen million, three hundred ten thousand".