Base | Representation |
---|---|
bin | 10110100011111111… |
… | …00110001100011101 |
3 | 1011021011211101220122 |
4 | 23101333212030131 |
5 | 144301414404003 |
6 | 5321544324325 |
7 | 606113114552 |
oct | 132177461435 |
9 | 34234741818 |
10 | 12113044253 |
11 | 5156552482 |
12 | 24207736a5 |
13 | 11b06c470b |
14 | 82ca46a29 |
15 | 4ad650238 |
hex | 2d1fe631d |
12113044253 has 4 divisors (see below), whose sum is σ = 12503787648. Its totient is φ = 11722300860.
The previous prime is 12113044219. The next prime is 12113044259. The reversal of 12113044253 is 35244031121.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35244031121 = 13 ⋅2711079317.
It is a cyclic number.
It is not a de Polignac number, because 12113044253 - 26 = 12113044189 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12113044259) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 195371651 + ... + 195371712.
It is an arithmetic number, because the mean of its divisors is an integer number (3125946912).
Almost surely, 212113044253 is an apocalyptic number.
It is an amenable number.
12113044253 is a deficient number, since it is larger than the sum of its proper divisors (390743395).
12113044253 is an equidigital number, since it uses as much as digits as its factorization.
12113044253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 390743394.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 12113044253 its reverse (35244031121), we get a palindrome (47357075374).
The spelling of 12113044253 in words is "twelve billion, one hundred thirteen million, forty-four thousand, two hundred fifty-three".
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