Base | Representation |
---|---|
bin | 10110100011111111… |
… | …00110001101110101 |
3 | 1011021011211102000220 |
4 | 23101333212031311 |
5 | 144301414404331 |
6 | 5321544324553 |
7 | 606113115036 |
oct | 132177461565 |
9 | 34234742026 |
10 | 12113044341 |
11 | 5156552552 |
12 | 2420773759 |
13 | 11b06c4778 |
14 | 82ca46a8d |
15 | 4ad650296 |
hex | 2d1fe6375 |
12113044341 has 4 divisors (see below), whose sum is σ = 16150725792. Its totient is φ = 8075362892.
The previous prime is 12113044337. The next prime is 12113044343. The reversal of 12113044341 is 14344031121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12113044341 - 22 = 12113044337 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12113044343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2018840721 + ... + 2018840726.
It is an arithmetic number, because the mean of its divisors is an integer number (4037681448).
Almost surely, 212113044341 is an apocalyptic number.
It is an amenable number.
12113044341 is a deficient number, since it is larger than the sum of its proper divisors (4037681451).
12113044341 is an equidigital number, since it uses as much as digits as its factorization.
12113044341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4037681450.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 12113044341 its reverse (14344031121), we get a palindrome (26457075462).
The spelling of 12113044341 in words is "twelve billion, one hundred thirteen million, forty-four thousand, three hundred forty-one".
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