Base | Representation |
---|---|
bin | 10001101000000111101… |
… | …101111001110000110001 |
3 | 11021210121021221101122202 |
4 | 101220013231321300301 |
5 | 124321230411013212 |
6 | 2324245050312545 |
7 | 153341253151634 |
oct | 21500755716061 |
9 | 4253537841582 |
10 | 1211310251057 |
11 | 427794070115 |
12 | 176915428755 |
13 | 8a2c288c05a |
14 | 428b06b9c1b |
15 | 21797b110c2 |
hex | 11a07b79c31 |
1211310251057 has 2 divisors, whose sum is σ = 1211310251058. Its totient is φ = 1211310251056.
The previous prime is 1211310251023. The next prime is 1211310251117. The reversal of 1211310251057 is 7501520131121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 766633331776 + 444676919281 = 875576^2 + 666841^2 .
It is a cyclic number.
It is not a de Polignac number, because 1211310251057 - 228 = 1211041815601 is a prime.
It is not a weakly prime, because it can be changed into another prime (1211310251357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605655125528 + 605655125529.
It is an arithmetic number, because the mean of its divisors is an integer number (605655125529).
Almost surely, 21211310251057 is an apocalyptic number.
It is an amenable number.
1211310251057 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211310251057 is an equidigital number, since it uses as much as digits as its factorization.
1211310251057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2100, while the sum is 29.
Adding to 1211310251057 its reverse (7501520131121), we get a palindrome (8712830382178).
The spelling of 1211310251057 in words is "one trillion, two hundred eleven billion, three hundred ten million, two hundred fifty-one thousand, fifty-seven".
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