Base | Representation |
---|---|
bin | 10001101000000111110… |
… | …001001001100001000111 |
3 | 11021210121100112121222000 |
4 | 101220013301021201013 |
5 | 124321231120231043 |
6 | 2324245120440343 |
7 | 153341263324611 |
oct | 21500761114107 |
9 | 4253540477860 |
10 | 1211311102023 |
11 | 4277945a14a0 |
12 | 1769157790b3 |
13 | 8a2c2ac9499 |
14 | 428b085bdb1 |
15 | 21797c2d2d3 |
hex | 11a07c49847 |
1211311102023 has 32 divisors (see below), whose sum is σ = 1957804608000. Its totient is φ = 734079153600.
The previous prime is 1211311102021. The next prime is 1211311102069. The reversal of 1211311102023 is 3202011131121.
It is not a de Polignac number, because 1211311102023 - 21 = 1211311102021 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1211311101987 and 1211311102005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1211311102021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4621803 + ... + 4876851.
It is an arithmetic number, because the mean of its divisors is an integer number (61181394000).
Almost surely, 21211311102023 is an apocalyptic number.
1211311102023 is a deficient number, since it is larger than the sum of its proper divisors (746493505977).
1211311102023 is a wasteful number, since it uses less digits than its factorization.
1211311102023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 271060 (or 271054 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 1211311102023 its reverse (3202011131121), we get a palindrome (4413322233144).
The spelling of 1211311102023 in words is "one trillion, two hundred eleven billion, three hundred eleven million, one hundred two thousand, twenty-three".
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