Base | Representation |
---|---|
bin | 10110100011111111… |
… | …11011101011001001 |
3 | 1011021011222212121011 |
4 | 23101333323223021 |
5 | 144301430212413 |
6 | 5321550243521 |
7 | 606113632216 |
oct | 132177735311 |
9 | 34234885534 |
10 | 12113132233 |
11 | 5156602594 |
12 | 24207b65a1 |
13 | 11b0725787 |
14 | 82ca6ab0d |
15 | 4ad66b33d |
hex | 2d1ffbac9 |
12113132233 has 2 divisors, whose sum is σ = 12113132234. Its totient is φ = 12113132232.
The previous prime is 12113132221. The next prime is 12113132243. The reversal of 12113132233 is 33223131121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12044623504 + 68508729 = 109748^2 + 8277^2 .
It is an emirp because it is prime and its reverse (33223131121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12113132233 - 225 = 12079577801 is a prime.
It is not a weakly prime, because it can be changed into another prime (12113132243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056566116 + 6056566117.
It is an arithmetic number, because the mean of its divisors is an integer number (6056566117).
Almost surely, 212113132233 is an apocalyptic number.
It is an amenable number.
12113132233 is a deficient number, since it is larger than the sum of its proper divisors (1).
12113132233 is an equidigital number, since it uses as much as digits as its factorization.
12113132233 is an evil number, because the sum of its binary digits is even.
The product of its digits is 648, while the sum is 22.
Adding to 12113132233 its reverse (33223131121), we get a palindrome (45336263354).
The spelling of 12113132233 in words is "twelve billion, one hundred thirteen million, one hundred thirty-two thousand, two hundred thirty-three".
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