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12113134135 = 52422626827
BaseRepresentation
bin10110100011111111…
…11100001000110111
31011021011222222012121
423101333330020313
5144301430243020
65321550300411
7606113640604
oct132177741067
934234888177
1012113134135
115156603a63
1224207b7707
1311b07265bb
1482ca6b6ab
154ad66bbaa
hex2d1ffc237

12113134135 has 4 divisors (see below), whose sum is σ = 14535760968. Its totient is φ = 9690507304.

The previous prime is 12113134097. The next prime is 12113134147. The reversal of 12113134135 is 53143131121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53143131121 = 253120996891.

It is a cyclic number.

It is not a de Polignac number, because 12113134135 - 213 = 12113125943 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1211313409 + ... + 1211313418.

It is an arithmetic number, because the mean of its divisors is an integer number (3633940242).

Almost surely, 212113134135 is an apocalyptic number.

12113134135 is a deficient number, since it is larger than the sum of its proper divisors (2422626833).

12113134135 is an equidigital number, since it uses as much as digits as its factorization.

12113134135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2422626832.

The product of its digits is 1080, while the sum is 25.

Adding to 12113134135 its reverse (53143131121), we get a palindrome (65256265256).

The spelling of 12113134135 in words is "twelve billion, one hundred thirteen million, one hundred thirty-four thousand, one hundred thirty-five".

Divisors: 1 5 2422626827 12113134135