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12113141 = 38331627
BaseRepresentation
bin101110001101…
…010011110101
3211210102002212
4232031103311
511100110031
61111343205
7204650165
oct56152365
924712085
1012113141
116923867
124081b05
132681651
1418745a5
1510e412b
hexb8d4f5

12113141 has 4 divisors (see below), whose sum is σ = 12145152. Its totient is φ = 12081132.

The previous prime is 12113119. The next prime is 12113147. The reversal of 12113141 is 14131121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14131121 = 73193577.

It is a cyclic number.

It is not a de Polignac number, because 12113141 - 218 = 11850997 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12113147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15431 + ... + 16196.

It is an arithmetic number, because the mean of its divisors is an integer number (3036288).

Almost surely, 212113141 is an apocalyptic number.

It is an amenable number.

12113141 is a deficient number, since it is larger than the sum of its proper divisors (32011).

12113141 is an equidigital number, since it uses as much as digits as its factorization.

12113141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32010.

The product of its digits is 24, while the sum is 14.

The square root of 12113141 is about 3480.3937995577. The cubic root of 12113141 is about 229.6601218173.

Adding to 12113141 its reverse (14131121), we get a palindrome (26244262).

The spelling of 12113141 in words is "twelve million, one hundred thirteen thousand, one hundred forty-one".

Divisors: 1 383 31627 12113141