Base | Representation |
---|---|
bin | 11011100010101100111101… |
… | …111101101001100000100011 |
3 | 120212220002212111200000122002 |
4 | 123202230331331221200203 |
5 | 111334111320032020232 |
6 | 1105343135033034215 |
7 | 34341332636246636 |
oct | 3342547575514043 |
9 | 525802774600562 |
10 | 121132002220067 |
11 | 35661880391863 |
12 | 1170423a55596b |
13 | 5278911340a27 |
14 | 21cab6a857c1d |
15 | e00dc48d0b62 |
hex | 6e2b3df69823 |
121132002220067 has 2 divisors, whose sum is σ = 121132002220068. Its totient is φ = 121132002220066.
The previous prime is 121132002220051. The next prime is 121132002220109. The reversal of 121132002220067 is 760022200231121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121132002220067 - 24 = 121132002220051 is a prime.
It is not a weakly prime, because it can be changed into another prime (121132002220367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60566001110033 + 60566001110034.
It is an arithmetic number, because the mean of its divisors is an integer number (60566001110034).
Almost surely, 2121132002220067 is an apocalyptic number.
121132002220067 is a deficient number, since it is larger than the sum of its proper divisors (1).
121132002220067 is an equidigital number, since it uses as much as digits as its factorization.
121132002220067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 29.
Adding to 121132002220067 its reverse (760022200231121), we get a palindrome (881154202451188).
The spelling of 121132002220067 in words is "one hundred twenty-one trillion, one hundred thirty-two billion, two million, two hundred twenty thousand, sixty-seven".
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